1.

A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of, -0.5 m/`s^(2)`. How much distance will be covered by the scooter before it stops ?

Answer» Here, Initial speed, `u` = 10 m/s
Final speed, `v` = 0 (Scooter stops)
Acceleration, `a` = -0.05 m/`s^(2)`
And, Distance covered, `s` = ? (To be calculated)
Now, putting these values in the third equation of motion :
`" "v^(2)=u^(2)+2as`
We get : `" "(0)^(2)=(10)^(2)+2xx(-0.5)xxs`
`" "0=100-s`
`" "s=100` m
Thus, the distance covered is 100 metres.


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