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A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of, -0.5 m/`s^(2)`. How much distance will be covered by the scooter before it stops ? |
Answer» Here, Initial speed, `u` = 10 m/s Final speed, `v` = 0 (Scooter stops) Acceleration, `a` = -0.05 m/`s^(2)` And, Distance covered, `s` = ? (To be calculated) Now, putting these values in the third equation of motion : `" "v^(2)=u^(2)+2as` We get : `" "(0)^(2)=(10)^(2)+2xx(-0.5)xxs` `" "0=100-s` `" "s=100` m Thus, the distance covered is 100 metres. |
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