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A screen is placed `50 cm` from a single slit, which is illuminated with `6000 Å` light. If the distance between the first and third minima in the diffraction pattern is `3.00 mm`, what is the width of the slit ?A. `1 xx 10^(-4)m`B. `2 xx 10^(-4)m`C. `0.5 xx 10^(-4)m`D. `4 xx 10^(-4)m` |
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Answer» Correct Answer - B The position of `n^(th)` minima in the diffraction pattern is `x_(n)=(n D lambda)/(d)` ` :. x_(3)-x_(1)=(3-1)(D lambda)/(d)=(2D lambda)/(d)` or `d=(2D lambda)/(x_(3)-x_(1))=(2xx0.50xx6000xx10^(-10))/(3xx10^(-3))=2xx10^(-4)m` |
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