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A screen is placed 50cm from a single slit, which is illuminated with 6000Å light. If distance between the first and third minima in the diffraction pattern is 3.0 mm, what is the width of the slit?A. `0.1mm`B. `0.2mm`C. `0.4mm`D. `0.8mm` |
Answer» Correct Answer - B Position of first minima on a single slit diffraction pattern is given by `d sin theta = n lambda` For small value of `theta, sin theta ~~ theta = (y)/(D)` `:. (y.a)/(D) = n lambda or y= (n lambda D)/(a)` `:.` Distance between third order minima and first order minima will bew `Delta y = y_(3)-y_(1) = ((3-1)(lambda D))/(a) = (2lambda D)/(a)` |
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