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A screw gauge gives the following reading when used to mesure the diametre of a wire. Main scale reading : `0mm` Circular scale reading : `52 divisions` Given that `1mm` on main scale corresponds to `100` divisions of the circular scale. the diameter of wire from the above data is :

Answer» Main scale reading `= 0mm`
Circular scale reading `= 52` divisions
Least count `= ("Value of 1 main scale division")/("Total divisions on circular scale") = (1)/(100) mm`
Diameter of wire `= M.S.R + (C.S.R xx L.C)`
`= 0 + 52 xx (1)/(100) mm = 0.52mm = 0.52cm`


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