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A screw guage gives the following reading when used to measure the diameter of a wire. Main scale reading : 0 mm Circular scale reading : 52 divisions The diameter of wire from the above data is(A) 0.52 cm (B) 0.052 cm (C) 0.026 cm (D) 0.005 cm |
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Answer» Answer is (B) 0.052 cm Least count of screw gauge = \(\frac{1}{100}\) mm = 0.01 mm Diameter = Main scale reading + (Divisions on circular scale x least count) = 0 + \(\Big(52\times\frac{1}{100}\Big)\) = 0.52 mm Diameter = 0.052 cm |
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