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A sealed container was filled with 1 mol of A_(2)(g) 1 mol B_(2)(g) at 800 K and total pressure 1.00 bar. Calculate the amounts of the components in the mixture at equilibrium given that K=1 for the reaction A_(2)(g)+B_(2)(g)hArr2AB(g)

Answer» <html><body><p></p>Solution :`A_(2)(g)+B_(2)(g)hArr2AB(g)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_CHE_XI_V02_C08_E01_050_S01.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> no. of moles `=1-x+1-x+<a href="https://interviewquestions.tuteehub.com/tag/2x-301182" style="font-weight:bold;" target="_blank" title="Click to know more about 2X">2X</a>=2` <br/> `K_(P)=((P_(AB))^(2))/((P_(A_(2)))(P_(B_(2))))=(((2x)/(2)xxP)^(2))/((((1-x))/(2)xxP)((1-x)/(2)xxP))` <br/> `K_(P)=(<a href="https://interviewquestions.tuteehub.com/tag/4x-319255" style="font-weight:bold;" target="_blank" title="Click to know more about 4X">4X</a>^(2))/((1-x)^(2))` <br/> Given that `K_(P)=1,(4x^(2))/((1-x)^(2))=1` <br/> `rArr4x^(2)=(1-x)^(2)` <br/> `rArr4x^(2)=1+x^(2)-2x` <br/> `3x^(2)+2x-1=0` <br/> `x=(-2pmsqrt(4-(4xx3xx-1)))/(2(3))` <br/> `x=(-2pmsqrt(4+12))/(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)` <br/> `=(-2pmsqrt(16))/(6)` <br/> `=(2)/(6),(-2-4)/(6)` <br/> `x=0.33,-1("not <a href="https://interviewquestions.tuteehub.com/tag/possible-592355" style="font-weight:bold;" target="_blank" title="Click to know more about POSSIBLE">POSSIBLE</a>")` <br/> `:.[A_(2)]_(eq)=1-x=1-0.33=0.67` <br/> `[B_(2)]_(eq)=1-x=1-0.33=0.67` <br/> `[AB]_(eq)=2x=2xx0.33=0.66`.</body></html>


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