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A second pendulum is attached to roof of a car that is moving with acceleration `10m//s^(2)` on a straight road. Its frequenct of oscillation isA. `(1)/(2)Hz`B. `1Hz`C. `(1)/(sqrt(2))Hz`D. `2^(-3//4)Hz` |
Answer» Correct Answer - D `f = (1)/(2pi) sqrt((sqrt(g^(2)+a^(2)))/(l))` |
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