1.

A seconds pendulum is placed in a space laboratory orbiting around the Earth at a height 3R from the Earth's surface where R is the radius of the Earth. The time period of the pendulum will be……………

Answer»

ZERO
`2//3s`
4 s
inifinite

Solution :In a SPACE laboratory `g=0`. Therefore, `T=2pisqrt((L)/(g))=oo`


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