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A seconds pendulum is suspended form the roof of a lift. If the lift is moving up with an acceleration `9.8 m//s^(2)`, its time period isA. `1s`B. `sqrt(2)`C. `(1)/(sqrt(2))s`D. `2sqrt(2)s` |
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Answer» Correct Answer - B `T = 2pi sqrt((l)/(g+a))` |
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