A sector of 56°, cut out from a circle, contains 17.6 cm2. Find the r – InterviewSolution

1.

A sector of 56°, cut out from a circle, contains 17.6 cm2. Find the radius of the circle.

Answer»

Area of the sector = 17.6 cm² (given)

We know, Area of the sector = θ/360 (πr²) square units

This implies,

θ/360 (πr²) = 17.6

56/360 x 22/7 x r² = 17.6

r² = 36

or r = 6

Radius of the circle is 6 cm.

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