A semiconductor has an electron concentration of `0.45 xx 10^(12) m^(-3)` and a hole concentration of `5.0 xx 10^(20) m^(-3)`. Calculate its conductivity. Given electron mobility `= 0.135 m^(2) V^(-1) s^(-1)`, hole mobility `= 0.048 m^(2) V^(-1) s^(-1)`,

A semiconductor has an electron concentration of `0.45 xx 10^(12) m^(-

1.	A semiconductor has an electron concentration of `0.45 xx 10^(12) m^(-3)` and a hole concentration of `5.0 xx 10^(20) m^(-3)`. Calculate its conductivity. Given electron mobility `= 0.135 m^(2) V^(-1) s^(-1)`, hole mobility `= 0.048 m^(2) V^(-1) s^(-1)`,
Answer» The conductivity of a semicon ductor is the sum of the conductivities due to electrons and holes and is given by `sigma = sigma_(e) + sigma_(h) =n_(e)e mu_(e) +n_(h) e mu_(h) =e(n_(e)mu_(e)+n_(h)mu_(h))` As per given date, `n_(e)` is negligible as compared to `n_(h)`, so that we can write `sigma = en_(h) mu_(h)` =`(1.6 xx 10^(-19) C) (5.0 xx 10^(20) m^(-3))(0.048 m^(2) V^(-1) s^(-1))` =`3.84 Omega^(-1) m^(-1) =3.84 m^(-1)`.

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A semiconductor has an electron concentration of `0.45 xx 10^(12) m^(-3)` and a hole concentration of `5.0 xx 10^(20) m^(-3)`. Calculate its conductivity. Given electron mobility `= 0.135 m^(2) V^(-1) s^(-1)`, hole mobility `= 0.048 m^(2) V^(-1) s^(-1)`,

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