A series L-C-R circuit with R = 120 Ω has an angular frequency of 4×105 rad/sec. At resonance, voltages across resistance and inductor are 60 V and 40 V respectively. If frequency at which the circuit current lags behind the voltage by a phase of π/4 radian is k × 105 rad/sec, then the value of k is (answer upto two decimal places)

A series L-C-R circuit with R = 120 Ω has an angular frequency of 4�

1.	A series L-C-R circuit with R = 120 Ω has an angular frequency of 4×105 rad/sec. At resonance, voltages across resistance and inductor are 60 V and 40 V respectively. If frequency at which the circuit current lags behind the voltage by a phase of π/4 radian is k × 105 rad/sec, then the value of k is (answer upto two decimal places)
Answer» A series L-C-R circuit with R = 120 $Ω$ has an angular frequency of $4 \times 10^{5}$ rad/sec. At resonance, voltages across resistance and inductor are 60 $V$ and 40 $V$ respectively. If frequency at which the circuit current lags behind the voltage by a phase of π/4 radian is $k \times 10^{5}$ rad/sec, then the value of $k$ is (answer upto two decimal places)

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