1.

A set of 24 tunning forks is arranged so that each gives 4 beats per second with the previous one and the last sounds the octave of first. Find frequency of 1st and last tunning forks.

Answer»

Let frequency of Ist tunning fork = x 

frequency of IInd tunning fork = x + 4 

frequency of IIIrd tunning fork = x + 2 (4) 

frequency of IVth tunning fork = x + 3 (4) 

∴ Let frequency of 24th tunning fork = x + 23 (4)

octave means, (twice in freq.)

∴  freq. of 24th = 2 × freq. of Ist = 2x

∴ 2x = x + 23 (4) ⇒ x = 92

freq. of 24th = 2 × 92 = 184 H3.



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