a shell is fired from a Cannon at an angle of 30 degree with horizonta – InterviewSolution

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1.	a shell is fired from a Cannon at an angle of 30 degree with horizontal velocity of 1000 metre per second assuming G equal to 10 metre per second find time taken by the shell to reach the highest point and how high the shell will arise
Answer» ux=ucos60o=100cos60oor ux=50m/sAt top MUST point the center of mass will have only horizontal component of velocity.( & this will be ux=50 m/s)If SHELL was of 3 mthen the FRAGMENT m will move upward with 200 m/sso to make Net velocity of center of mass zero in vertical direction mx200+2mxvy=0or vy=−100 m/s i.e downward.only the bigger part is possessing the horizontal component of velocity so m+2mmx0+2mvx=ux⇒Vx=23ux=75 m/sspeed=ux2+vy2=752+(−100)2=125 m/s

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