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A shell of mass 200 gm is ejected from a gun of mass 4 kg by an explosion that generates 1.05 kJ of energy. Calculate the initial velocity of the shell

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> Data: <br/> m= 200 gm = 0.2 kg , M=<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> kg, <br/> `"Energy <a href="https://interviewquestions.tuteehub.com/tag/generated-2093392" style="font-weight:bold;" target="_blank" title="Click to know more about GENERATED">GENERATED</a>" 1.05 KJ =1.05 xx 10^(3) J` <br/> According to <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of Conservation of linear momentum <br/> `mv=Mv^(.)` <br/> `:. v^(.)=((m)/(M))v` <br/> Total K.E of the <a href="https://interviewquestions.tuteehub.com/tag/gun-1014044" style="font-weight:bold;" target="_blank" title="Click to know more about GUN">GUN</a> and bullet <br/> `=(1)/(2)Mv^(.2)+(1)/(2)mv^(2)` <br/> `=(1)/(2)M((m)/(M)v)^(2)+(1)/(2)mv^(2)` <br/> `=(1)/(2)(m^(2)v^(2))/(M)+(1)/(2)mv^(2)` <br/> `=(1)/(2)mv^(2)[(m)/(M)+1]` <br/> `(1)/(2) xx 0.2 xx v^(2)[1+(0.2)/(4)]=1.05 xx 10^(3)J` <br/> `:. v^(2)=(4 xx 1.05 xx 1000)/(0.1 xx 4.2)=100^(2)` <br/> `v=100 m // s`</body></html>


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