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A ship of mass 3 x 107 kg initially at rest is pulled by a force of 5 x 104 N through a distance of 3 m. Assuming that the resistance due to water is negligible. What will be the speed of the ship. (1) 0.1 m/sec. (2) 1.5 m/sec. (3) 5 m/sec. (4) 60 m/sec. |
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Answer» Answer is (1) 0.1 m/sec. F = ma 5 x 104 = 3 x 107 x a. a = (5/3) x 10-3 m/s2; s = 3m, u = 0 ν2 = u2 + 2as = 2 x (5/3) x 10-3 x 3 ⇒ ν2 = 10-2 ⇒ ν = 0.1 m/s. |
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