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InterviewSolution
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A shopkepper sells three types of flower seeds `A_(1),A_(2) and A_(3)`. They are sold as mixture, where the proportion are 4 : 4 : 2, respectively. The germination rates of the three types of seeds 45%, 60% and 35%. Calculate the probability (i) of a randomly chosen seed to germinate. (ii) that it will not germinate given that the seed is of type `A_(3)`. (iii) that it is of the type `A_(2)` given that a randomly chosen seed does bot germinate |
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Answer» W have, `A_(1) : A_(2) : A_(3)=4 : 4 : 2` `P(A_(1))=4/10,P(A_(2))=4/10and P(A_(3))=2/10` where `A_(1),A_(2) and A_(3)` denote the three types of flower seeds. Let E be the event that aseeed germinbates and `barE` be the event that a seed does not germinate. `thereforeP(E//A_(1))=45/100,P(E//A_(2))=60/100and P(E/A_(3))=35/100` and `P(barE//A_(1))=55/100,P(barE//A_(2))=40/100and P(barE/A_(3))=65/100` (i) `therefore P(E)=P(A_(1))cdotP(E//A_(1))+P(A_(2))cdotP(E//A_(2))+P(A_(3))cdotP(E/A_(3))` `=4/10cdot45/100+4/10cdot60/100+2/10cdot35/100` `=180/1000+240/1000+70/1000=490/1000=0.49` (ii) `P(barE//A_(3))=1-P(E//A_(3))=1-P(E//A_(3))=1-35/100=65/100` [as given above] (iii) `P(A_(2)/barE)=(P(A_(2))cdotP(barE//A_(2)))/(P(A_(1))cdotP(barE//A_(1))+P(A_(2))cdotP(barE//A_(2))+P(A_(3))cdotP(barE//A_(3)))` `=(4/10cdot40/100)/(4/10cdot55/100+4/10cdot40/100+2/10cdot65/100)=(160/1000)/(220/1000+160/1000+130/1000)` `=(160//1000)/(510//1000)=16/51=0.313725=0.314` |
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