A short bar magnet has a magnetic moment of 0.48 JT-1. Give the dire

1.	A short bar magnet has a magnetic moment of 0.48 JT-1. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on (i) the axis (ii) the equatorial lines (normal bisector) of the magnet.
Answer» Given: m = 0.48 JT^-1, r = 10 cm = 0.1 m To find: i. Magnetic induction along axis (B_a) ii. Magnetic induction along equator (B_eq) Formulae: i. Ba = \(\frac{\mu_0}{4\pi}\,\frac{2m}{r^3}\) ii. B_a = 2 B_eq Calculation: From formula (i), B_a = 10^-7 × \(\frac{2\times0.48}{10^{-3}}\) ∴ B_a = 0.96 × 10^-4 T along S-N direction From formula (ii), B_eq = \(\frac{0.96\times106-4}{2}\) ∴ B_eq = 0.48 × 10^-4 T along N-S direction

A short bar magnet has a magnetic moment of 0.48 JT-1. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on (i) the axis (ii) the equatorial lines (normal bisector) of the magnet.

Answer»

Given: m = 0.48 JT^-1, r = 10 cm = 0.1 m

To find:

i. Magnetic induction along axis (B_a)

ii. Magnetic induction along equator (B_eq)

Formulae:

i. Ba = \(\frac{\mu_0}{4\pi}\,\frac{2m}{r^3}\)

ii. B_a = 2 B_eq

Calculation: From formula (i),

B_a = 10^-7 × \(\frac{2\times0.48}{10^{-3}}\)

∴ B_a = 0.96 × 10^-4 T along S-N direction

From formula (ii),

B_eq = \(\frac{0.96\times106-4}{2}\)

∴ B_eq = 0.48 × 10^-4 T along N-S direction

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A short bar magnet has a magnetic moment of 0.48 JT-1. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on (i) the axis (ii) the equatorial lines (normal bisector) of the magnet.

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