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A short bar magnet of magnetic moment `0*9JT^-1` is placed with its axis at `30^@` to a uniform magnetic field. It experiences a torque of `0*063J`. Calculate the magnitude of magnetic field. In which orientation will the bar magnet be in stable equilibrium in the magnetic field? |
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Answer» Here, `M=0*JT^-1, theta=30^@` `tau=0*063J, B=?` `tau=MB sin theta, B=(tau)/(Msintheta)=(0*063)/(0*9xxsin30^@)` `=0*14T` For stable equilibrium, the magnetic moment `vecM` of magnet must be parallel to magnetic field `vecB`. |
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