A short bar magnet placed with its axis at `30^@` to a uniform magnetic field of `0*2T` experiences a torque of `0*06N-m`. Calculate magnetic moment of the magnet. What orientation of magnet corresponds to its stable equilibrium in the magnetic field?

A short bar magnet placed with its axis at `30^@` to a uniform magneti

1.	A short bar magnet placed with its axis at `30^@` to a uniform magnetic field of `02T` experiences a torque of `006N-m`. Calculate magnetic moment of the magnet. What orientation of magnet corresponds to its stable equilibrium in the magnetic field?
Answer» Here, `theta=30^@, B=02T`, `tau=006N-m, M=?` From `tau=Mbsintheta`, `M=(tau)/(B sin theta)=(006)/(02 sin 30^@)=0*6Am^2` Potential energy of magnetic dipole `U=-MB cos theta` In stable equilibrium, P.E. is minimum `:. cos theta=1` or `theta=0^@` i.e., bar magnet will be in stable equilibrium. when its magnetic moment `vecM` is parallel to magnetic field `vecB`.

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A short bar magnet placed with its axis at `30^@` to a uniform magnetic field of `0*2T` experiences a torque of `0*06N-m`. Calculate magnetic moment of the magnet. What orientation of magnet corresponds to its stable equilibrium in the magnetic field?

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A short bar magnet placed with its axis at `30^@` to a uniform magnetic field of `02T` experiences a torque of `006N-m`. Calculate magnetic moment of the magnet. What orientation of magnet corresponds to its stable equilibrium in the magnetic field?