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A short linear object of length b lies along the axis of a concave mirror or focal length f at a distance u from the pole of the mirror. The size of the image is approximately equal toA. `(f/(u-f))b`B. `(f/(u-f))^(2)b`C. `(f/(u-f))b^(2)`D. `(f/(u-f))` |
Answer» Correct Answer - B (b) Using mirror formula, `1/v+1/(-u)=1/(-f)` Multiplying with u, `u/v=(-u)/f)+1=(f-u)/f` `therefore` Magnification, m=`v/u=(f/(f-u))` Now, `abs(dv)=m^(2)abs(du)` Sizze of image=`(f/(f-u))^(2)`cdotb` |
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