1.

a shunt generator gives full load out put of  30 kw of a terminal voltage of 200 volt. The armature and shunt fild resistance are 0.05 ohm and 50 ohm respectively. the iron  and friction losses are 1000 watt . calculate the generated emf, Cooper losses,effeciency

Answer»

Line current IL = 30*1000/200 = 300A

If = 200/50 = 4A

Armature current Ia = IL - If = 300-4 = 296A

Induced EMF = V + IaRa

=200 + 296*0.05 = 214.8V

 Copper losses = 0.05*296*296 = 4380 W

Efficiency = Output power / input power +losses

= 30*1000 / (30000+5380) = 85%



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