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a shunt generator gives full load out put of 30 kw of a terminal voltage of 200 volt. The armature and shunt fild resistance are 0.05 ohm and 50 ohm respectively. the iron and friction losses are 1000 watt . calculate the generated emf, Cooper losses,effeciency |
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Answer» Line current IL = 30*1000/200 = 300A If = 200/50 = 4A Armature current Ia = IL - If = 300-4 = 296A Induced EMF = V + IaRa =200 + 296*0.05 = 214.8V Copper losses = 0.05*296*296 = 4380 W Efficiency = Output power / input power +losses = 30*1000 / (30000+5380) = 85% |
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