A silica glass rod has a diameter of 1 cm and is 10 cm long. Estimate

1.	A silica glass rod has a diameter of 1 cm and is 10 cm long. Estimate the largest mass that can be hung from it without breaking it.
Answer» Breaking strength of glass is 50 × 10⁶ Nm^-2 Using Stress = \(\frac{F}{A}\), We get F = stress × A = (50 × 10⁶) × π × \((\frac{10^{-2}}{2})N\) Largest mass = \(\frac{(50\times 10^6)(\frac{π\times 10^{-4}}{4})}{10}kg\) = 392.7 kg

A silica glass rod has a diameter of 1 cm and is 10 cm long. Estimate the largest mass that can be hung from it without breaking it.

Answer»

Breaking strength of glass is 50 × 10⁶ Nm^-2

Using Stress = \(\frac{F}{A}\),

We get F = stress × A

= (50 × 10⁶) × π × \((\frac{10^{-2}}{2})N\)

Largest mass = \(\frac{(50\times 10^6)(\frac{π\times 10^{-4}}{4})}{10}kg\)

= 392.7 kg