A silicon specimen is made into a `P`-type semiconductor by dopping, on an average, one helium atoms per `5xx10^(7)` silicon atoms. If the number density of atoms in the silicon specimen is `5xx10^(28) at om//m^(3)` then the number of acceptor atoms in silicon per cubic centimeter will beA. `2.5xx10^(30) at oms//cm^(3)`B. `1.0xx10^(13) at oms//cm^(3)`C. `1.0xx10^(15) at oms//cm^(3)`D. `2.5xx10^(36) at oms//cm^(3)`

A silicon specimen is made into a `P`-type semiconductor by dopping, o

1.	A silicon specimen is made into a `P`-type semiconductor by dopping, on an average, one helium atoms per `5xx10^(7)` silicon atoms. If the number density of atoms in the silicon specimen is `5xx10^(28) at om//m^(3)` then the number of acceptor atoms in silicon per cubic centimeter will beA. `2.5xx10^(30) at oms//cm^(3)`B. `1.0xx10^(13) at oms//cm^(3)`C. `1.0xx10^(15) at oms//cm^(3)`D. `2.5xx10^(36) at oms//cm^(3)`
Answer» Correct Answer - C Number density of a atoms in silicon specimen `=5xx10^(28) at ms//m^(3)=5xx10^(22)//cm^(3)` Since one atom of indium is dopped in `5xx10^(7) Si` atom. So number of indium atoms dopped per `cm^(3)` of silicon. `n=(5xx10^(22))/(5xx10^(7))=1xx10^(15) at om//cm^(3)`

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