A Simple aromatic hydrocarbon A reacts with Cl_2 to give B of molecular formula C_6H_5Cl. B on reaction with ethyl chloride along with sodium metal gives C of formula C_8H_10.C alone reacts with Na metal in the presence of ether to give D C_12 H_10. Identify A,B,C & D.

A Simple aromatic hydrocarbon A reacts with Cl_2 to give B of molecula

1.	A Simple aromatic hydrocarbon A reacts with Cl_2 to give B of molecular formula C_6H_5Cl. B on reaction with ethyl chloride along with sodium metal gives C of formula C_8H_10.C alone reacts with Na metal in the presence of ether to give D C_12 H_10. Identify A,B,C & D.
Answer» Solution : (i) The simple aromatic HYDROCARBON is `C_6H_6` Benzene (A) (ii) Benzene reacts with `Cl_2` to give chlorobenzene. `C_6H_6 + Cl_2 overset(FeCl_2) to underset("benzene")underset("Chloro")(C_6H_5Cl) + HCl_B` (III) Chlorobenzene reacts with ethyl CHLORIDE to FORM ethyl benzene, C as the product. `C_6H_5Cl + 2 Na+ C_2H_5Cl overset("ether")to underset("Ethyl benzene C")(C_6H_5- C_2H_5) + 2NaCl` (iv) Chlorobenzene on reaction Na metal gives Biphenyl compound D as the product. `C_6H_5Cl + 2Na + C_6H_5Clto underset("Biphenyl D")(C_6H_5-C_2H_5) + 2NaCl`