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A simple harmonic oscillation is represented by the equation:y = 0.40 sin (440 t + 0.61),where y and t are in metre and second respectively. What are the values of (i) amplitude, (ii) angular frequency,. (iii) frequency of oscillations, (iv) time period of oscillations and (v) initial phase? |
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Answer» The given equation is y = 0.40 sin (440 t + 0.61) Comparing it with the equation of S.H.M y = a sin (ωt + ϕ0) We have (i) amplitude, a = 0.40 m (ii) Angular frequency, ω = 440 Hz (iii) Frequency of oscillations v = ω/2π = {440}/{2 x 22/7} = 70 Hz (iv) Time period of oscillations, T = 1/v = 1/70 = 0.0143 s. (v) Initial phase angle, ϕ = 0.61 rad |
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