1.

A simple harmonic oscillator consist of a particle of mass m and an ideal spring with spring constant k. The particle oscillates with a time period T. The spring is cut into two equal parts. If one part oscillates with the same particle, the time period will be...........

Answer»

`T//2`
`(T)/(sqrt(2))`
`sqrt(2)T`
2T

Solution :`T=2pisqrt((m)/(K))`
If the SPRING is CUT into TWO equal parts, the force constant of each part becomes 2K. Therefore,
`T.=2pisqrt((m)/(2k))=(T)/(sqrt(2))`


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