1.

A simple harmonic oscillator has a period of 0.01 s and an amplitude of 0.2 m. The magnitude of the velocity in m/s at the centre of oscillation is……………….

Answer»

`20pi`
`40pi`
`60pi`
`80pi`

SOLUTION :VELOCITY is maximum at the CENTRE of oscillation and is given by
`v_(0)=(2pi)/(T)A=(2pixx0.2)/(0.01)=40pim//s`


Discussion

No Comment Found