1.

A simple harmonic oscillator has its displacement varying as x = 15 sin `(2pit+pi//4)` metre. Then its initial displacement isA. 15 mB. `15//sqrt(2) m`C. `15 sqrt(2) m`D. `7.5 m`

Answer» Correct Answer - B
`x=15sin(2pit+(pi)/(4))`
`=15sin(2pixx0+(pi)/(4))`
`=15sin.(pi)/(4)`
`=15xx(1)/(sqrt(2))=(15)/(sqrt(2))m`


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