A simple harmonic progressive of frequency 100 Hz and wavelength 0.5 m

1.	A simple harmonic progressive of frequency 100 Hz and wavelength 0.5 m travels through a medium. If the path difference between two points in the path of the wave is 0.1 m, what is the corresponding phase difference ?
Answer» Path difference = \(\frac{2\pi}\lambda\) x phase difference = \(\frac{2\pi}{0.5\,m}\) x 0.1 m = 0.4 rad

A simple harmonic progressive of frequency 100 Hz and wavelength 0.5 m travels through a medium. If the path difference between two points in the path of the wave is 0.1 m, what is the corresponding phase difference ?

Answer»

Path difference = \(\frac{2\pi}\lambda\) x phase difference

= \(\frac{2\pi}{0.5\,m}\) x 0.1 m = 0.4 rad