A simple pendulum 4 m long swing with an amplitude of 0.2 m. What is its acceleration at the ends of its path? (g = 10 m//s^(2))

A simple pendulum 4 m long swing with an amplitude of 0.2 m. What is i

1.	A simple pendulum 4 m long swing with an amplitude of 0.2 m. What is its acceleration at the ends of its path? (g = 10 m//s^(2))
Answer» Solution :`T= mgcostheta` `:. F_("net")= mgsintheta` and acceleration = gsintheta `= (10)(0.2)/(4)= 0.5 m//s^(2)`