A simple pendulum 4 m long swing with an amplitude of 0.2 m. What is its acceleration at the ends of its path? (g=10m//s^(2))

A simple pendulum 4 m long swing with an amplitude of 0.2 m. What is i

1.	A simple pendulum 4 m long swing with an amplitude of 0.2 m. What is its acceleration at the ends of its path? (g=10m//s^(2))
Answer» SOLUTION :`T=mgcos theta` `:.F_("NET")=MG sin theta` and acceleration `=g sin theta` `=(10)((0.2))/4=0.5m//s^(2)`