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A simple pendulum from earth is shifted to moon (g_(m) = g_(g)//6). Foreign minute on earth, the time on the moon as measured by the pendulum is (For same number of oscillations) |
Answer» <html><body><p>24.5 <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a><br/>2.45 sec<br/>245 sec<br/>147 sec </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |