A simple pendulum has a time periodT_(1).when its point of suspension is moved vertically upwards according as y=kt^(2) where y is vertical distance covered and k = 1 ms^(-2) , its time period becomes T_(2) , Then , (T_(1)^(2))/(T_(2)^(2)) " is " (g=10ms^(-2))

A simple pendulum has a time periodT_(1).when its point of suspension

1.	A simple pendulum has a time periodT_(1).when its point of suspension is moved vertically upwards according as y=kt^(2) where y is vertical distance covered and k = 1 ms^(-2) , its time period becomes T_(2) , Then , (T_(1)^(2))/(T_(2)^(2)) " is " (g=10ms^(-2))
Answer» `5/6` `(11)/(10)` `6/5` `5/4` ANSWER :C