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A simple pendulum has time period T_(1). The point of suspension is now moved upwards according to the relation y=Kt^(2),(K=1m*s^(-2)) where y is the vertical displacement. The time period now becomes T_(2). The ratio of T_(1)^(2)//T_(2)^(2) is (g=10m*s^(-2)) |
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Answer» `6/5` |
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