A simple pendulum has time period T1. The point of suspension is now moved upward according to the relation y=kt2(k=1m/s2), where y is the vertical displacement. The time period now becomes T2. The ratio of T21T22 is considered to be x. Then the value of 5x is ___. (Take g=10m/s2)

A simple pendulum has time period T1. The point of suspension is now m

1.	A simple pendulum has time period T1. The point of suspension is now moved upward according to the relation y=kt2(k=1m/s2), where y is the vertical displacement. The time period now becomes T2. The ratio of T21T22 is considered to be x. Then the value of 5x is ___. (Take g=10m/s2)
Answer» A simple pendulum has time period $T_{1}$ . The point of suspension is now moved upward according to the relation $y = k t^{2} (k = 1 m / s^{2})$ , where y is the vertical displacement. The time period now becomes $T_{2}$ . The ratio of $\frac{T_{1}^{2}}{T_{2}^{2}}$ is considered to be x. Then the value of 5x is ___. (Take $g = 10 m / s^{2}$ )

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A simple pendulum has time period T1. The point of suspension is now moved upward according to the relation y=kt2(k=1m/s2), where y is the vertical displacement. The time period now becomes T2. The ratio of T21T22 is considered to be x. Then the value of 5x is ___. (Take g=10m/s2)

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