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A simple pendulum having caharge ` q_1` mass ma and effective length `1`, is suspended from a rigid support between the plates of charged horizontal capacitor. Electric field in the capacitor is perpendicular to the plates and directed vertically downwards . If the plates are oriented such thet plates made an angel ` theta` with the horizontal then the new time period of the oscillation of the pendulum is give by .A. ` T= 2 pi sqrt(l/sqrt (g^2 + ((qE)/m)^2 + 2g ((qQ)/m) sin theta)`B. ` T= 2 pi sqrt(l/sqrt (g^2 + ((qE)/m)^2 + 2g ((qQ)/m) sin theta)`C. ` T= 2 pi sqrt(l/sqrt (g^2 + ((qE)/m)^2 + 2g ((qQ)/m) sin theta)`D. |
Answer» Correct Answer - B | |