A simple pendulum is formed by hanging a sphere of mass of 1 kg from a copper wire of length 5 m and of diameter, 0.08 cm and then the time period of this pendulum is measured. Now the sphere of mass 1 kg is replaced by another sphere of mass 10 kg. Determine the change in time period of the pendulum. [ Y for copper = 12.4xx10^(10)N*m^(-2)]

A simple pendulum is formed by hanging a sphere of mass of 1 kg from a

1.	A simple pendulum is formed by hanging a sphere of mass of 1 kg from a copper wire of length 5 m and of diameter, 0.08 cm and then the time period of this pendulum is measured. Now the sphere of mass 1 kg is replaced by another sphere of mass 10 kg. Determine the change in time period of the pendulum. [ Y for copper = 12.4xx10^(10)N*m^(-2)]
Answer» ANSWER :4.488 s, 0.0035 s