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A simple pendulum is oscillating with amplitue A and angular frequency `omega` At ratio of kinetic energy to potential energy isA. `(x^(2))/(A^(2)-x^(2))`B. `(x^(2)-A^(2))/(x^(2))`C. `(A^(2)-x^(2))/(x^(2))`D. `(A-x)/(x)` |
Answer» Correct Answer - C `(KE)/(PE)=((1)/(2)momega^(2)[A^(2)-x^(2)])/((1)/(2)momega^(2)x^(2))=(A^(2)-x^(2))/(x^(2))` |
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