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A simple pendulum is oscillating with angular displacement `90^(@)` For what angle with vertical the acceleration of bob direction horizontal?A. `sin^(-1)((1)/(3))`B. `cos^(-1) ((1)/(3))`C. `sin^(-1)((1)/(sqrt(3)))`D. `cos^(-1)((1)/(sqrt(3)))` |
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Answer» Correct Answer - D `tan theta = (a_(c ))/(a_(t)) = (v^(2)//r)/(g sin theta)` but `v^(2) = 2 gh`, `h = r cos theta` |
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