A simple pendulum is suspended from the roof of a school bus which movies in a horizontal direction with an acceleration a, then the time period is :

A simple pendulum is suspended from the roof of a school bus which mov

1.	A simple pendulum is suspended from the roof of a school bus which movies in a horizontal direction with an acceleration a, then the time period is :
Answer» `T=prop(1)/(g^(2)+a^(2))` `T=prop(1)/(SQRT(g^(2)+a^(2)))` `Tpropsqrt(g^(2)+a^(2))` `Tprop(g^(2)+a^(2))` SOLUTION :According to law of ACCELERATION, the time period of simple PENDULUM `Tprop(1)/(sqrt(g))` From phythagoras THEOREM, `g.=g^(2)+a^(2)` `g.^(2)=sqrt(g^(2)+a^(2))` `Tprop(1)/(sqrt((sqrt(g^(2)+a^(2))))),Tprop(1)/(g^(2)+a^(2))`