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A simple pendulum of length 1 m is oscillated at a place where g=9.8m//s^(2). Find the maximum velocity of the bob of the simple pendulum if the amplitude of oscillation is 3 cm. |
Answer» <html><body><p>`5.219cms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`7.216cms^(-1)`<br/>`6.181cms^(-1)`<br/>`9.391cms^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |