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A simple pendulum of length `4.9m` is immersed in a liquid of density `rho =0.4 kg//m^(3)`. Then the time period of pendulum is (density of bob `=0.8 kg//m^(3))`A. `pi s`B. `3pi s`C. `2 pi s`D. `pi//2s` |
Answer» Correct Answer - A `T = 2pi sqrt((l)/(g_(eff)))` where `g_(eff) = g (1-(rho)/(sigma))` |
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