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A simple pendulum of length `l_(1)` has frequency 1/4 Hz and another simple pendulum of length `l_(2)` has frequency 1/3 Hz. Then time period of pendulum of length `(l_(1)-l_(2))` isA. 5 sB. 1 sC. `sqrt(7) s`D. `sqrt(12) s` |
Answer» Correct Answer - A `(n_(1))/(n_(2))=sqrt(l_(2)/(l_(1)))` `(16)/(9)=(l_(2))/(l_(1))` `(16+9)/(9)=(l_(2)+l_(1))/(l_(1))` `(25)/(9)=(l_(2)+l_(1))/(l_(1))` `(5)/(3)=(l_(2)+l_(1))/(l_(1))` |
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