A simple pendulum of length l is suspended to the ceiling of a lift moving upward with an acceleration of (g//6). Find the time period of its oscillation?

A simple pendulum of length l is suspended to the ceiling of a lift mo

1.	A simple pendulum of length l is suspended to the ceiling of a lift moving upward with an acceleration of (g//6). Find the time period of its oscillation?
Answer» Solution :As lift is moving UPWARDS, time PERIOD is given by `T= 2pisqrt((L)/(g+a))= 2pisqrt((l)/(g+(g)/(6)))= 2pisqrt((6L)/(7g))`