A simple pendulum of length l is suspended to the ceiling of a lift moving upward with an acceleration of (g/6). Find the time period of its oscillation?

A simple pendulum of length l is suspended to the ceiling of a lift mo

1.	A simple pendulum of length l is suspended to the ceiling of a lift moving upward with an acceleration of (g/6). Find the time period of its oscillation?
Answer» Solution :As lift is MOVING upwards , time period is given by T= `2pi SQRT(l/(g+a)) = 2pi sqrt((l)/(g+ g/6)) = 2pi sqrt((6L)/(7G))`