1.

A simple pendulum of length L swings in a vertical plane. The tension of the string when it makes an angle theta with the vertical and the bob of mass m moves with a speed v is (g is the gravitational acceleration)

Answer»

`mv^(2)//L`
`mgcostheta+mv^(2)//L`
`mgcostheta-mv^(2)//L`
`mgcostheta`

Solution :
At point P, the resultant of the tension in the string (T) and the COMPONENT of weight `(mgcostheta)` provide the necessary CENTRIPETAL force for the CIRCULAR motion of the bob.
i.e., `T-mgcostheta=(mv^(2))/Lor,T=mgcostheta+(mv^(2))/L`


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