1.

A simple pendulum of mass m and length l stands in equilibrium in vertical position. The maximum horizontal velocity that should be given to the bob at the bottom so that it completes one revolution is(A)  \(\sqrt{lg}\)(B)  \(\sqrt{2lg}\)(C)  \(\sqrt{3lg}\)(D)  \(\sqrt{5lg}\)

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Answer is  (D)  \(\sqrt{5lg}\)



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