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A simple pendulum oscillates with an amplitude of `2xx10^(-2)m`. If the force acting on it at extreme position is 4 N. Then the time that another simple pendulum of length 81 cm takes to execute the same number of oscillations isA. 4NB. 3NC. 2ND. 1N |
Answer» Correct Answer - C `(F_(m))/(F_(e))=(kx_(m))/(kx_(e))` `=((A)/(2))/(A)=(1)/(2)` `F_(m)=(F_(e))/(2)=(4)/(2)=2N` |
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