A simple pendulum perform simple harmonic motion about x=0 with an amplitude A and time period T. The speed of the pendulum at x= (A)/(2) will be……….

A simple pendulum perform simple harmonic motion about x=0 with an amp

1.	A simple pendulum perform simple harmonic motion about x=0 with an amplitude A and time period T. The speed of the pendulum at x= (A)/(2) will be……….
Answer» `(pi A)/(T)` `(3pi^(2) A)/(T)` `(pi A sqrt(3))/(T)` `(pi A sqrt(3))/(2T)` Solution :`v= OMEGA sqrt(A^(2)-x^(2))= (2pi)/(T) sqrt(A^(2)-(A^2)/(4))` `=(2pi)/(T) sqrt((3A^2)/(4))= (pi A sqrt(3))/(T)`.